{填空}求数组a中偶数的个数和偶数的平均值

#include <stdio.h>
int main(void)
{int k=0;float ave,s=0;
int a[10]={1,2,3,4,5,6,7,8,9,10};
for (i=0;i<10,i++)
{if (a[i]%2==1)continue; //奇数跳过
s+=a[i]; //偶数累加到s上
k++;} //偶数k增加一来计数
if(k!=0)
{ave =s/k;
printf("k=%d,ave=%f\n\",k,ave();}
return 0;}